Today, 20 June 2016, at 22:34 UTC (01:34 ISS) is expected to be the summer solstice – the longest day of the year in SP (astronomical summer) and the shortest day of the year in the SH (astronomical winter).
On this day the maximum height of the Sun and the height of the shadow at noon from the object a height of 1 meter in latitude is equal to:
For the Northern hemisphere:
Latitude 90 degrees North pole = 23.5 degrees (polar day);
Shadow height: 2.3 meters
Latitude 60 degrees – 53.5 degrees;
Shadow height: 74 cm
Latitude 45 degrees is 68.5 degrees;
Height of shade: 39 cm
Latitude 30 degrees – tropics – 83.5 degree;
Height of shade:11 cm
Latitude 23.5 degrees – 90 degrees
The height of the shadow: the SHADOW is MISSING (SUN IN ZENITH).
Latitude 0 degrees – the equator – of 113.5 degrees (23.5 degrees North of Zenith).
The height of the shadow:
For the southern hemisphere:
Latitude 23.5 degrees – 43 degrees;
The height of the shadow: a little more than 1 m.
Latitude 30 degrees – tropics – 36,5 degrees;
Shadow height: 1,35 meter
Latitude 45 degrees 21.5 degrees;
The height of the shadow – 2,53 meters
Latitude 60 degrees to 6.5 degrees;
Shadow height: 8.7 meters.
Latitude 90 degrees South pole is minus 23.5 degrees (the polar night).
The height of the shadow: NO
Photo: the view of the Earth on the morning of 20 June 2016.
*The formula for calculating the maximum altitude of the Sun at noon on the summer solstice June 20 (SP):
H = 90-latitude +23.5 per = 113,5-latitude.
*The formula for calculating the maximum altitude of the Sun at noon on the winter solstice June 20 (UP):
H= 90-latitude – 23.5 per = 66,5 – latitude
*The formula to calculate the height of the shadow from the object at noon:
L = h/tgA
h – object height, the length of whose shadow is measured;
tgA is the tangent of the angle of the Sun.
For the subject is at a height of 1 m. the formula is still more simplified view:
L=ctgA.
